![]() And because we don't have uh the population size is not large enough compared to that sample size, we need to know multiply it by that, that would be 100 and 39 divided by 100 and 88 square rooted. And so when we put that in, we have the 9.7 minus 2.1 times 6.2 divided by the square root of 50. Um and next we need to multiply by the traditional standard air which would end up being that 6.2 divided by the square root of an But then we need to multiply it by that correction factor of 189 minus the sample size. ![]() It was a normal distribution, it would be 1.96, so it's a little bit bigger than that. And now we have our T value with 49 degrees of freedom and having 490.0 to 5 in the upper tail, that's corresponding to 2.10. ![]() So we're going to have 9.7 plus or minus. So we have to use that correction factor. ![]() And so we can see that this is more than 5% of the population. And they have sampled 50 people and found that the main billing overtime hours was 9.7 with the sample standard deviation of 6.2. So we want to find in part a 95% confidence interval for the population mean? And we have the Population size is 189.
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